Posted by farich azhar | Posted in . . . | Posted on 07.14
Tentukan kenaikan titik didih 800 ml larutan yang mengandung 4,5% massa NaOH!(diketahui ? = 1,08 kg/,Kb air=0,52°c/m,Mr NaOH=40).
Jawab:
Massa larutan NaOH
= ? x v
= 1,08 x 0,8
= 0,864 Kg
= 864 g
Massa NaOH
= % x massa larutan
= 4.5% x 864
= 38,88 g
Massa air
= 864 – 38,88
= 825,12 g
Molalitas NaOH
= g/Mr x 1000/P
= 38,88/40 x 1000/825,12
= 1,178 m
Kenaikan titik didih larutan
= m.Kb. I
= 1,178 x 0,52 x 2
= 1,225 oC
Jadi kenaikan titik didih larutannya adalah 1,225 oC
